- cross-posted to:
- programmerhumor@lemmy.ml
- cross-posted to:
- programmerhumor@lemmy.ml
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This was gonna be my response to OP so I’ll offer an alternative approach instead:
typedef enum flags_e : unsigned char { F_1 = (1 << 0), F_2 = (1 << 1), F_3 = (1 << 2), F_4 = (1 << 3), F_5 = (1 << 4), F_6 = (1 << 5), F_7 = (1 << 6), F_8 = (1 << 7), } Flags; int main(void) { Flags f = F_1 | F_3 | F_5; if (f & F_1 && f & F_3) { // do F_1 and F_3 stuff } }
Why not
if (f & (F_1 | F_3)) {
? I use this all the time in embedded code.edit: never mind; you’re checking for both flags. I’d probably use
(f & (F_1 | F_3)) == (F_1 | F_3)
but that’s not much different than what you wrote.